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(C) $(I)$ $CH_3O-CH_2^+$ is stabilized by resonance due to the lone pair on oxygen,making it more stable than the primary carbocation $CH_3-CH_2^+$. S

Vedclass · Accepted Answer

$I, II$ and $III$ are correct

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(C) $(I)$ $CH_3O-CH_2^+$ is stabilized by resonance due to the lone pair on oxygen,making it more stable than the primary carbocation $CH_3-CH_2^+$. Statement $(I)$ is correct.$(II)$ $Me_2CH^+$ is a secondary carbocation,which is more stable than the primary carbocation $CH_3-CH_2-CH_2^+$ due to hyperconjugation and inductive effects. Statement $(II)$ is correct.$(III)$ $CH_2=CH-CH_2^+$ is an allyl carbocation,which is stabilized by resonance,making it more stable than the primary carbocation $CH_3-CH_2-CH_2^+$. Statement $(III)$ is correct.$(IV)$ $CH_2=CH^+$ is a vinylic carbocation where the positive charge is on an $sp$-hybridized carbon. This is highly unstable compared to the $sp^3$-hybridized primary carbocation $CH_3-CH_2^+$. Statement $(IV)$ is incorrect.Therefore,statements $(I), (II),$ and $(III)$ are correct.

Consider the following statements. Of these statements:
$(I) \ CH_3O-CH_2^+$ is more stable than $CH_3-CH_2^+$
$(II) \ Me_2CH^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(III) \ CH_2=CH-CH_2^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(IV) \ CH_2=CH^+$ is more stable than $CH_3-CH_2^+$

Similar Questions

The order of decreasing stability of the carbanions is:
$1.$ $(CH_3)_3C^-$
$2.$ $(CH_3)_2CH^-$
$3.$ $CH_3CH_2^-$
$4.$ $C_6H_5CH_2^-$

The correct order of stability for the following carbanions is:
$CH_2=CH^{-}, CH_3-CH_2^{-}, CH\equiv C^{-}$

Which free radical is most stable among the following?

Define carbocation,carbanion,and free radical.

What is the correct order of stability for the given carbocations?
$(i) \ CH_3^+ \quad (ii) \ CH_3CH_2^+ \quad (iii) \ CH_3OCH_2^+$

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Consider the following statements. Of these statements:$(I) \ CH_3O-CH_2^+$ is more stable than $CH_3-CH_2^+$$(II) \ Me_2CH^+$ is more stable than $CH_3-CH_2-CH_2^+$$(III) \ CH_2=CH-CH_2^+$ is more stable than $CH_3-CH_2-CH_2^+$$(IV) \ CH_2=CH^+$ is more stable than $CH_3-CH_2^+$